Stair Pressurization Calculator 🪜

Size the stairwell pressurization fan from closed-door leakage, wall leakage and the open-door velocity criterion, then check the door opening force — using the leakage method of NFPA 92 and EN 12101-6.

🧮 Inputs

Stair
Open doors (velocity criterion)
Allowances & door force
Leakage areas: EN 12101-6 Annex A. Wall leakage ratios: ASHRAE smoke control data. The knob is assumed 75 mm from the latch edge.
Auto calculate enabled (no Calculate button).
Required Supply Airflow
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Supply (m³/h)
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incl. allowances
Supply (CFM)
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Door Opening Force
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Preliminary sizing only. The final design must be verified against the adopted code, the authority having jurisdiction and commissioning tests; a pressure relief path or variable-speed control is needed so the pressure does not exceed the door-force limit when all doors close.

Airflow Breakdown

Closed stair doors
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Final exit door(s)
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Stair walls
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Unidentified leakage
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Open door(s) at velocity
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Duct / fan leakage
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Total
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Door Force & Injection

Max ΔP allowed by door force
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Suggested injection points
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Air to relieve when all doors close
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How Stair Pressurization Is Sized

A pressurized stair has to meet two conditions at once. With the doors closed, the stair must be held above the floors by a minimum pressure difference so smoke cannot leak in. With one or more doors open, enough air must flow out through the open doorway to push smoke back. The fan is sized for the sum of both, plus allowances for leakage nobody can measure in advance.

  • Leakage through a closed door or crack: Q = 0.83 × A × ΔP1/2 (m³/s, A in m², ΔP in Pa)
  • Leakage through walls: Q = 0.83 × Aw × ΔP1/1.6
  • Open door: Q = v × W × H × number of open doors
  • Door opening force: F = Fdc + W·A·ΔP ÷ [2(W − d)]

Minimum Pressure Difference

NFPA 92 sets the minimum pressure difference across a smoke barrier at 12.4 Pa (0.05 in. w.g.) in a sprinklered building. In a non-sprinklered building the minimum rises with ceiling height because hotter, more buoyant smoke pushes harder: about 25 Pa for a 2.7 m ceiling. EN 12101-6 Class A systems commonly design to 50 Pa with doors closed and 0.75 m/s through the open door. Use the class or value your code and authority require — the presets are starting points.

Why Door Force Limits the Pressure

More pressure is not always safer. Every pascal across a door pushes against the person trying to open it into the stair. NFPA 101 caps the opening force at 133 N (30 lbf); many EN-based specifications use 100 N. The tool reports the maximum pressure difference the door allows with the closer force you entered — if your design ΔP is above it, a person may not be able to open the door to escape.

This is also why a pressurized stair needs a relief path or a variable-speed fan: the airflow sized for an open door has nowhere to go when that door closes, and the pressure climbs above the door-force limit.

Single vs Multiple Injection

Air injected only at the bottom of a tall stair leaves through the first open door it meets, and the upper floors lose pressure. Tall stairs are therefore fed at several levels; one supply point every three floors is a common rule. The tool suggests a number of injection points on that basis and splits the airflow evenly.

Worked Example

10-floor stair, sprinklered (12.5 Pa), single-leaf doors opening out of the stair (0.02 m²), one exit door, average walls, 22 m perimeter × 3.5 m floors, one 0.9 × 2.1 m door open at 1.0 m/s.

  • Closed doors: 9 (one is open) × 0.83 × 0.02 × √12.5 = 0.528 m³/s
  • Exit door: 0.83 × 0.02 × √12.5 = 0.059 m³/s
  • Walls: 22 × 3.5 × 10 × 0.00011 = 0.0847 m² → 0.83 × 0.0847 × 12.50.625 = 0.341 m³/s
  • Open door: 1.0 × 0.9 × 2.1 = 1.89 m³/s

With 25% unidentified and 15% duct leakage the fan needs about 3.5 m³/s (≈ 7,430 CFM), split over four injection points.

FAQ

What pressure difference is required for stair pressurization?

NFPA 92 requires at least 12.4 Pa in sprinklered buildings and higher values in non-sprinklered buildings (about 25 Pa for a 2.7 m ceiling). EN 12101-6 Class A systems typically use 50 Pa with doors closed.

What is the maximum door opening force?

NFPA 101 limits it to 133 N (30 lbf) at the latch. Many EN-based specifications use 100 N. The force includes the door closer, so a strong closer leaves less room for pressure.

Why does a pressurized stair need pressure relief?

The fan is sized for an open door. When every door closes, that air has no outlet and the pressure rises until doors become too hard to open. A barometric relief damper, a vent to outside or a variable-speed fan controlled by a pressure sensor prevents it.

How many supply points does a stairwell need?

Short stairs can work with a single injection point. Tall stairs are usually fed at several levels, commonly one point every three floors, so an open door near the fan does not starve the upper floors.

Can this calculator replace a smoke control design?

No. It gives a preliminary fan size. Stack effect, wind, building leakage, lobby and lift shaft interaction and commissioning test results all affect the final design and must be checked by the engineer of record.

📚 References

  • NFPA 92: Standard for Smoke Control Systems — minimum design pressure differences (Table 4.4.2.1.1)
  • NFPA 101 7.2.1.4.5: maximum door opening force 133 N (30 lbf)
  • EN 12101-6: Smoke and heat control systems — pressure differential systems (leakage areas, Annex A)
  • ASHRAE Handbook of Smoke Control Engineering: flow through leakage paths, Q = C·A·√(2ΔP/ρ)
  • ASHRAE Handbook – HVAC Applications, Smoke Control chapter: typical leakage area ratios for stairwell walls

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